$${\mathtt{8}}{\mathtt{\,\times\,}}\left({\mathtt{\,-\,}}{\frac{{\mathtt{3}}}{{\mathtt{2}}}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{6}}\right) = {\mathtt{\,-\,}}\left({\mathtt{9}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{4}}}{{\mathtt{3}}}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{8}}\right)\right) \Rightarrow \left\{ \begin{array}{l}\end{array} \right\}$$
.
) 