IAmJeff

I agree with guest here. One time i typed my name as Iamjeff and not IAmJeff and it said "unknown username"

Just make sure you get it 100% right.

I cry even thinking of math

Thanks!

Alright, so first set up the equation a^2+b^2=c^2

In this equation AR equals a, so put 7 in for a. GA equals c, so put 10 in for c.

You get 7^2+b^2=10^2

From that you get 49+b^2=100

Minus 49 from both sides to get b^2=51

We know that the square root of 51 will be an irational number, so GR is the square root of 51.

You can solve it from there.

72/9=s

Ok, all of these are relativaly simple.

The formula you will be working with for all of these is a^2+b^2=c^2

Im not going to give you the answers only explain how to do it.

#1. 28 and 21 are a and b. Insert them into the formula to get 28^2+21^2=c^2

Solve for 28^2+21^2 and get 1225

now you are at 1225=c^2

Your answer will be the square root of 1225.

#2. In this problem 6 and 7 are a and b.

Put them in the equation above to get 36+49=c^2

Your answer for this will be the square root of 85

#3. In this problem 2 times the square root of 3 is c and the square root of 3 is a.

Put them into the equation above to get the square root of 3 squared (3) + b^2=2times the square root of 3 squared (2 times the square root of 3.

This gets us to the Square root of 3+ b^2=2 times the square root of 3

Minus Square root of 3 from right side to get b^2 equals the square root of three. so b equals the square root of the square root of three

Have A nice day!