KnockOut

So we know that our slope is \(-2\). 

Point slope form is in the form of \((y-y_1) = m(x - x_1)\).

Using our coordinate (I'm going to choose \((1 , 14)\) ), and plugging it into the formula, we get our point-slope form to be

\(\boxed{y-14 = -2(x-1)}\).

Okay, let's solve this one.

I would personally choose the coordinates \((1 , 14)\) and \((2 , 12)\), because they are going to make my life much easier than using coordinates that have decimals in them. Therefore, when we find the slope, we have zero rounding to do.

Now, we are going to use the formula \(m = \frac{y_2 - y_1}{x_2 - x_1}\) to find the slope, \(m\).

Plugging in our numbers, we get \(m = \frac{12 - 14}{2 - 1}\), which is equal to \(\boxed{-2}\).

Hello.

Since I do not know if by x2 you meant \(2x\) or \(x^2\), I'll solve for both.

Okay. here is the solution for when it is \(2x\):

If the length is 5ft, then \(x = 5\).

Using this to solve for \(5x^3 + 4 - 2x\), we get \(625 + 4 - 10 = 619\).

The perimeter is \(5 + 5 + 619 + 619 = \boxed{1248}\) ft.

Now, here is the solution for when it is \(x^2\).

If the length is 5ft, then \(x = 5\).

Using this to solve for \(5x^3 + 4 - x^2\), we get \(625 + 4 - 25 = 604\).

The perimeter is \(5 + 5 + 604 + 604 = \boxed{1218}\) ft. 

(2) looks good, except for the fact that the inequality sign must be a "less than or equal to".

(If you meant to type that)

You can do this next time, using:

\leq

in LaTeX. (\(\leq\))

For (1), the slope is \(\frac{3}{2}\).

Therefore, our answer would be something in the form of: \(y = \frac{3}{2}x + b\).

Converting this to standard form, we get \(-\frac{3}{2}x + y - b > 0\), which is \(-3x + 2y - 2b >0\).

Now the \(y\) intercept is found by plugging in a coordinate into the equation.

Solving this, we get the y-intercept to be 7.

So your answer for (1) would be correct.