You mean\(\dfrac{1}{2}\times \dfrac{4}{3}\times \pi \times 253-\dfrac{2}{3}\times \pi \times 253\)?
\(\dfrac{1}{2}\times \dfrac{4}{3}\times \pi \times 253-\dfrac{2}{3}\times \pi \times 253\\ = \dfrac{2\times 253\times \pi}{3}-\dfrac{2\times 253\times \pi}{3}\\ = 0\)
\(\frac{12}{15}\div \frac{4}{45}\\ = \frac{\not4}{\not5}\times \frac{\not{45}^{\;9}}{\not4\;}\)
= 9.
Same as Omi67's answer.
That means if an angle in a right-angled triangle is 49 degrees, and hypotenuse of the triangle = 5, the side opposite to the 49-degree angle is 3.773547901115.And this diagram:
Firstly, q is not an angle, it is the length of a side of a triangle.
\(\sin 49 = \dfrac{q}{5}\\ q=5\sin 49\)
No formula required.
5 sin 49 ≈ 3.773547901115
Just a guess.
604? :D
And this diagram: 