MaxWong

You mean$\dfrac{1}{2}\times \dfrac{4}{3}\times \pi \times 253-\dfrac{2}{3}\times \pi \times 253$?

$\dfrac{1}{2}\times \dfrac{4}{3}\times \pi \times 253-\dfrac{2}{3}\times \pi \times 253\\ = \dfrac{2\times 253\times \pi}{3}-\dfrac{2\times 253\times \pi}{3}\\ = 0$

$\frac{12}{15}\div \frac{4}{45}\\ = \frac{\not4}{\not5}\times \frac{\not{45}^{\;9}}{\not4\;}$

= 9.

Same as Omi67's answer.

That means if an angle in a right-angled triangle is 49 degrees, and hypotenuse of the triangle = 5, the side opposite to the 49-degree angle is 3.773547901115.And this diagram: 

Firstly, q is not an angle, it is the length of a side of a triangle.

$\sin 49 = \dfrac{q}{5}\\ q=5\sin 49$

No formula required.

5 sin 49 ≈ 3.773547901115

Just a guess.

604? :D