MaxWong

a in terms of b:

a=2b

a in terms of c:

a=3c

b in terms of a:

a=2b

b = 0.5a

b in terms of c:

2b = 3c

b = 1.5c

c in terms of a:

a=3c

c=\(\frac{1}{3}a\)

c in terms of b:

\(2b=3c\)

\(c=\frac{2}{3}b\)

\(t-3.4=7.6\)

\(t-3.4+3.4=7.6+3.4\)

\(t=11\)

Don't use the quad. formula because i have a faster way.

In the quad. eq. ax²+bx+c=0

Sum of the 2 sol. = \(-\frac{b}{a}\)

Product of the 2 sol. = \(\frac{c}{a}\)

a and b are the 2 roots of the equation in your question.

Let's make it \(\alpha\)and\(\beta \)

\(\frac{1}{2\alpha}+\frac{1}{2\beta}\)

= \(\frac{\alpha+\beta}{2\alpha\beta}\)

=\(\frac{-\frac{-8}{2}}{\frac{(2)(7)}{2}}\)

= \(\frac{4}{7}\)

First, find the number of boys.

176-96 = 80.

Therefore,

Girls:Boys

= 96:80

= 6:5

Yes I agree with you for some reasons. (And why the title is Cheese. xD)

Adding a positive number is just the same subtracting a corresponding negative number.

It depends on:

How big is the lolipop,(Radius?)

the rate you lick the lolipop,(Speed?)

and the area of your tongue, (Cross-sectional Area?)

Also, \(\sqrt{15241578750190521}=123456789\)

\(100000000+20000000+3000000+400000+50000+6000+700+80+9=123456789\)

\(666666666-543209877=123456789\)

\((\sqrt{123456790}+1)(\sqrt{123456790}-1)=123456789\)

\(123456789+0=123456789 \)

\(123456789\times1=123456789\)

Our Guest,

What can we help you with?

B(rackets):

4+3x5-6^4/(4+2)^3x2

= 4+3x5-6^4/6^3x2

E(xponents):

4+3x5-6^4/6^3x2

= 4+3x5-1296/216x2

D(ivisions):

4+3x5-1296/216x2

= 4+3x5-6x2

M(ultiplications):

4+3x5-6x2

= 4+15-12

A(dditions):

4+15-12

= 19-12

S(ubtractions):

19-12

= 7

\(sinh(19.324)\)

it approximately equals 123456789