MaxWong

What did we forget? jillybean

\(\frac{1}{4(a+10)}=2a-4\\ \frac{1}{a+10}=8a-16\\(8a-16)(a+10)=1\\ 8a^2+64a-160=1\\ 8a^2+64a-161=0\\ a=\frac{-64\pm\sqrt{64^2-4(8)(-161)}}{2(8)}\\ \;\;=\frac{-64\pm68\sqrt2}{16}\\ \;\;=-4\pm\dfrac{17\sqrt2}{4}\)

\(\frac{1}{4}(a+10)=2a-4 \\a+10=8a-16\\7a=26\\a=\dfrac{26}{7}\)

Googolplex is an extremely big number so that the calculator on this site could not express it.

Good answer Guest #2! :D

What kind of help do you need? Could you please explain more about your question?

Firstly, k must be a square number(1, 4, 9, ... etc.)

Next, we will analyze the second term of the trinomial.

-20x = \(2\times 2x\times (\text{Something})\)

\((\text{Something})= -5\)

Next, we will find the square of that (Something).

\(\boxed{(-a)^2=a^2}\\ (-5)^2=5^2=25\)

Therefore k = 25.

4x^2 - 20x + 25 = \((2x)^2-2\times 2x \times (-5)+(-5)^2=(2x-5)^2\)

\(\boxed{-a\div\dfrac{-1}{b}=ab}\)

\(-7\div\dfrac{-1}{9}=7\times9 = 63\)

\(\dfrac{2.981 \times 10^{20}}{3.25\times 10^3}\\=\dfrac{29.81\times10^{19}}{3.25\times10^3}\\=\dfrac{29.81}{3.25}\times\dfrac{10^{19}}{10^3}\\= \dfrac{2981}{325}\times 10^{16}\\\approx 9.1723\times 10^{16}\)

15.5563492 × (cos 135° + i sin 135°) according to the great Wolfram Alpha.

So it's A?

2016300