MaxWong

Hello. 

$5\frac{1}{2}\times 12\\ = \frac{11}{2}\times 12\\ = 11\times 6\\= 66$

$\log_216\\ = \log_22^4\\ = 4\\ \neq 8\\ \therefore\text{False.}$

$\log_42\\=\log_44^{1/2}\\=\frac{1}{2}\\ \therefore \text{True.}$

$2\log_2 47 \\ = \log_2 47^2\\ \neq 47\\ \therefore \text{False.}$

$\log_39 + \log_3\frac{1}{27}\\ =\log_33^2+\log_33^{-3}\\ = 2 + (-3)\\ = -1\\\neq 1/2\\ \therefore \text{False.}$

$\frac{-6x+1}{-2x+1}\text{ doesn't equal }\frac{3x}{1x}\text{. }$

$\text{Geno's answer is correct. This equation have no solutions.}$

Also your question is uncomprehendable.

Please do not type your question in another question. This will interrupt the users answering this question and it is rude.

2 + 2 

That is 4.

$\frac{3}{4}+\frac{5}{8}\\ = \frac{6}{8}+\frac{5}{8}\\ = \frac{6+5}{8}\\ = \frac{11}{8}\\ = 1\frac{3}{8}$

And that's definitely not hard.

#4 have no answer, there are 2 variables but only 1 representation.

#6. 

$x\times x + 2x - 35 = 0\\ x^2 + 2x - 35 = 0\\ (x+7)(x-5)=0\\ x=-7\\ \text{OR}\\ x=5$

None is the answer for #6.

#7. 

$\sqrt3^{\sqrt2}\times \sqrt3^{(-\sqrt2)}\\ =\sqrt3^{\sqrt2} \times \dfrac{1}{\sqrt3^{\sqrt2}}\\ = 1$

#7 answer = C

#8. 

$\sqrt2^{\sqrt2^{\sqrt2}}\\ \text{First we need to find what's }\sqrt2^{\sqrt2}\\ \sqrt{2}^{\sqrt{2}}\\ = 2^{\frac{1}{2}^\sqrt{2}}\\ = 2^{\frac{\sqrt2}{2}}\\ \mbox{We will do the same thing to }\sqrt2^{\sqrt2^{\sqrt2}}\\ \sqrt2^{\sqrt2^{\sqrt2}}\\ ={2^{\frac{\sqrt2}{2}}}^{\sqrt2}\\ =2^{\frac{\sqrt2^2}{2}}\\ = 2^1\\=2$

#8 answer = A

#9.

 $\sqrt2^{-9+3}\\ =2^{\frac{-6}{2}}\\ =2^{-3}\\ =\frac{1}{8}$

#9 answer = B

#10. Given the 2 angles are supp. Therefore the sum of 2 angles is 180 degrees.

$(x-15)^{\circ}+2x^{\circ}=180^{\circ}\\ (3x-15)^{\circ}=180^{\circ}\\ 3x^{\circ}=195^{\circ}\\ x^{\circ}=65^{\circ}$

Therefore #10 answer = A

$\begin{array}{rlll}&5&6&7\\+&2&3&4\\-&-&-&-\\&8&0&1\end{array}$