NinjaDevo

"A number, x, squared is 39 more than the product of 10 and x."

"is" means equals, or can be written as =

"more than" mean addition, or +

"product of" means multiplication, or *

Now we have:

x² = 39 + 10*x

x² = 39 + 10x

Well, we have already solved for T, so we can now solve for d.

We don't have enough information to numerically solve for T and d, but we can find what, say, d equals in terms of T.

So, to solve for d, here's what we do:

T = 1/4d^1/2              ---Raise both sides to the 2nd power to get rid of the ^1/2 of the right side

T^2 = 1/4d                ---Multiply both sides by 4 to get d alone

4*T^2 = d

4T^2 = d

so:

d = 4T^2

What are we solving for here? d?

$$8=d^{\frac{1}{2}}$$

Raise both sides to the 2nd power:

$$8^2 = (d{^\frac{1}{2}})^2$$

$$8^2 = d^{\frac{1}{2}\times2}$$

$$8^2 = d^{\frac{2}{2}}$$

$$8^2 = d$$

$$64 = d$$

So:

$$\mathbf{d = 64}$$

First, add 5 and 7 together.

$$5+7 = 12$$

Then, add 1/4 and 1/2 together.

$$\frac{1}{4} + \frac{1}{2}$$

The problem here is that we don't have a common denominator ( or common bottom number). To fix this, multiply the top and bottom of the second fraction by 2. We can do this as long as we do it to the top and bottom of the fraction.

$$\frac{1}{4} + \frac{1\times2}{2\times2}$$

$$\frac{1}{4} + \frac{2}{4}$$

Now we can add them together. Just add the tops together and keep the bottom number the same.

$$\frac{1+2}{4}$$

$$\frac{3}{4}$$

Finally, we add the two answers (12 and 3/4) together. We can't add them together evenly, so we write the answer as:

$$12\frac{3}{4}$$

First simplify the point coordinates to make this easier to look at/solve.

Point h:

(5(1/2),-4(1/4))

(5/2),(-4/4))

(5/2),(-1)

Point x:

(3(3/4), -1(1/4))

(9/4),(-1/4)

Now we have to use the midpoint formula, which basically adds the x values of both points, then divides them by 2.

You then do this to the y values too. Here's a picture showing you the midpoint formula:

Let's put in the values of your two points:

$$(\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$$

$$(\frac{\frac{5}{2} + \frac{9}{4}}{2},\frac{-1 + -\frac{1}{4}}{2})$$

$$(\frac{\frac{10}{4} + \frac{9}{4}}{2},\frac{-\frac{4}{4} + -\frac{1}{4}}{2})$$

$$(\frac{\frac{19}{4}}{2},\frac{-\frac{5}{4}}{2})$$

$$({\frac{19}{4}}\times\frac{1}{2},{-\frac{5}{4}}\times\frac{1}{2})$$

$$({\frac{19}{8}},{-\frac{5}{8})$$

Looks like the midpoint is $$(\frac{19}{8}, -\frac{5}{8})$$ or $$(2\frac{3}{8}, -\frac{5}{8})$$

It would come out to -15.

Say you owe someone $9, (which is -9) then tomorrow you owe that person $6 more (which is the -6)

How much do you owe them now? Well, you owe them $15 so the answer is -15.

Whenever your measuring distance, or something like it, you abolute the numbers your subtracting.

For example, say you have these two numbers on a number line and you want to find the distance.

You wouldn't just do -2 -1 to find the distance, because that would give you -1 and that doesn't make any sense.

You would want to do |-2 -1| which would be |-1| and then 1. The distance is 1. That makes more sense.

Anyway, let's apply this to your question. The temps. range from -122 to 30. To find the difference, subtract them in absolute values.

|-122 - 30|

|-152|

152

So the difference in the temps. on Mars is 152 degrees celcius.

Good job Dragon, but you didn't explain how to solve it. I have a feeling you just typed that into a calculator.

Here's how you solve it:

$$\frac{(a +a)}{(a\times a)}=\frac{1}{3}$$

Simplify:

$$\frac{2a}{a^2} = \frac{1}{3}$$

Divide the top and bottom by a:

$$\frac{2a \div a}{a^2 \div a} = \frac{1}{3}$$

$$\frac{2}{a} = \frac{1}{3}$$

Multiply both sides by a:

$$\frac{2}{a}\times a = \frac{1}{3}\times a$$

$$2 = \frac{1}{3} \times a$$

Multiply both sides by 3:

$$2\times3=1\times a$$

$$6 = a$$

So:

$$\mathbf{a = 6}$$