NinjaDevo

We need to find a common denominator to figure this out. A common demoninator is where the bottom number of both fractions are the same.

You might be thinking, "5 isn't a fraction though!" Well, it turns out that any whole number can be written as a fraction if you put it over 1. So to write 5 as a fraction it would be:

$$\frac{5}{1}$$

So now we have:

$$\frac{13}{3} - \frac{5}{1}$$

There's a problem though, the bottom number isn't the same. To fix this, multiply the top and bottom of the second fraction by 3. You can do this as long as you do it to both the top and bottom.

$$\frac{13}{3} - \frac{5\times3}{1\times3}$$

$$\frac{13}{3} - \frac{15}{3}$$

Now that we have the common demoninator, we can subtract the tops of the fractions, and put that over 3.

$$\frac{13-15}{3}$$

$$\frac{-2}{3}$$

which is the same thing as:

$$\mathbf{-\frac{2}{3}}$$

x is an unknown. We never know what x is until we solve. To do this we have to balance out both sides, so if we subtract 6 from one side, we have to subract 6 from the other side. If we multiply one side by 7, we have to multiply the other side by 7 too.

To solve this one, we have to add 2 to both sides to get x alone. You always want to get x alone because then you know what it equals.

23=x-2 

+2   +2

-------------

23+2=x

25=x

which means that

x = 25

Verbs show action or a state of being. Without them, nothing will happen. Literally!

Think about it, try to form a sentence without a verb. I believe it is possible, but it is very difficult.

Verbs are essential for sentence structure, and that is why we need them.

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This errors because you have two equals signs. I'm not sure what your asking really...can you be a little more spesific?

True that.

$$\frac{1}{4} \times \frac{3}{2} \times \frac{8}{9}$$

Start by "simplifying" if you can like so:

$$\frac{1}{{\not}4\;1} \times \frac{3}{2} \times \frac{{\not}8\;2}{9}$$

$$\frac{1}{1} \times \frac{3}{2} \times \frac{2}{9}$$

We can do this again with the 3 and 9 like so:

$$\frac{1}{1} \times \frac{{\not}3\;1}{2} \times \frac{2}{{\not}9\;3}$$

$$\frac{1}{1} \times \frac{1}{2} \times \frac{2}{3}$$

Multiply the tops together. Then multiply the bottoms together:

$$\frac{1\times1\times2}{1\times2\times3}$$

$$\frac{2}{6}$$

Now reduce the fraction by dividing the top and bottom by 2:

$$\frac{2\div2}{6\div2}$$

$$\frac{1}{3}$$

And that's that!

There's been some other questions like this. Check how we solved these and see if you can use that to solve this one for yourself. As always, let us know if you are still stuck.

What CPhill said. :)

If you're dividing a fraction, you can multiply by the recriprocal of that fraction. Or, in other words, flip the second fraction. Here's how you'd solve this:

$$\frac{-3}{7}\div \frac{11}{35}$$

Flip the second fraction and multiply:

$$\frac{-3}{7}\times \frac{35}{11}$$

Reduce the fractions:

$$\frac{-3}{{\not}7}\times \frac{{\not}35 \;5}{11}$$

$$\frac{-3}{1}\times \frac{5}{11}$$

$$\frac{-3\times5}{1\times11}$$

$$\frac{-15}{11}$$

$$-\frac{15}{11}$$

or

$$-1\frac{4}{11}$$