qjin27

You can find your answer by multiplying the probabilities. The first box she has a \(\frac{11}{12}\) chance of liking it, and the second box she has a \(\frac{9}{10} \), chance of liking it. The theoretical probability that she chooses 2 chocolates that she enjoys is \(\frac{99}{120}=\boxed{\frac{33}{40}}\)

There are 6 multiples of 8 below 50. 8, 16, 24, 32, 40, 48. There is a 44/50 chance that he doesn't choose 8 the first time. The second time is also a 44/50 chance he doesn't choose 8. so the probability that he doesn't choose at least 1 multiple of 8 is (44/50)^2=0.7744. so the probability that he chooses at least 1 multiple of 8 is 1-0.7744=\(\boxed{0.2256}\)

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