Let's say the number of children that entered the park is \(c\)
The total price of all the children's fees is, well, \(1.5c\)
Same for adults, the varible is \(a\), and the total price is \(4a\)
Now we have two equations
\(1.5c + 4a = 808 \)
\( c+a=272\)
Easy enough to solve
\(c=112, a=160\)
The number of children admitted is 112, and the total number of aldults admitted is 160
Check my work:
\(112+160=272\)
and \(168+640=808\)
(168 is 112 times 1.5, and 640 is 4 times 160)
Children = 112
Adults = 160
Please correct me if I'm wrong
