Skgr136

Mean is the average of a set of numbers. Median is the number in which 50% of the values in the set are higher than it and 50% of the values in the set are lower than it i.e. the middle number. The mode is the number that appears the most.

For example, in the set of numbers: 5, 5, 9, 11, 17

The mean is 9.4.

The median is 9.

The mode is 5.

e, also called Euler's number, is a mathematical constant that is used in calculus and natural logarithms. It is approximately equal to 2.72. You can probably learn more about it with a quick Google search if you search 'Euler's number'

The square root button is to the left of the x² button. It looks like a checkmark with an x next to it.

Thanks, it seems I took the derivative wrong.

I'm not sure how the proper way to do it in school is, but for unfamiliar decimals like 0.108 you can turn it into fraction actually pretty easily. Since the decimals go out to the thousandths place, that means that your denominator is 1000 and the 3 digits are your numerator.

So 108/1000 is the fraction form. This can then by reduced to 27/250

When we learned how to convert fractions to decimals in school, we used long division, but I don't know what you guys use now.

Oh I see. I added 7 and 6 when I was supposed to multiply.

Use the chain rule.

g'(g(x)) multiplied by g'(x)

Replace all the x's with 1

g(1) equals 2 so plug that into the chain rule to get:

g'(2) multiplied by g'(1)

Now plug in g'(2) and g'(1)

7 plus 6 equals 13.

So 13 is your answer.

Well the chain rule is f(g(x))' = f'(g(x)) × g'(x)

The derivative of the cos function is the negative sin function. So the first part is -Asin(wt + sigma)

Then take the derivative of the function inside the parenthesis to get w since the derivative of wt with respect to the is w, and the derivative of sigma is 0 assuming it is a constant.

Therefore the derivative of the entire function is -Awsin(wt + sigma).

This may be wrong since I am just learning about derivatives, but it is what I would do.

I'm assuming by expression, you mean something like 3 + 2.

If you have a fraction, say, 4/5, it could also be expressed as (2+2)/5

Most of the time, you should simplify the expression as much as possible since it is easier to understand a simpler fraction rather than a fraction with pluses and minuses and multiplication signs.

Interesting, I'd probably have to learn a bit more about what a matrix is to understand though

Interested to see how it is worked out. I have only briefly (VERY briefly) learned about matrices back in Algebra II and I've never heard of them since.

At the bottom I meant to say "The factors of x⁶ + 729 are 3i and -3i."

Okay so what you are going to want to do is move the 729 to the other side of the problem as I showed above to get:

x⁶ = -729

Now since you only deal with complex (imaginary) numbers when you take the square root of a negative number, we are going to have to change this equation so we can take the square root of what is on the right side.

That means we need to change the x⁶ to an x² and to do that you have to take the cubed (third) root. The cubed root of x⁶ is x² since 2 goes into 6 three times.

Now we need to take the cubed root of -729 as well which equals -9.

So now we have ----> x² = -9

Now we can take the square root of both sides to get:

x = plus or minus sqrt(-9) ----> (Remember when you take the square root of something it can be either plus or minus)

Now when you take the square root of a negative number, you do the same thing you do with a positive number but you just add an i.

So x = plus or minus 3i

So the factors of x⁶ are 3i and -3i

x⁶ + 729 does not have any real factors. You know this because if you move 729 to the other side of the equation you get: ----> x⁶ = -729 And you cannot take the sixth root (or any even numbered root) of a negative number.

If the problem wants you to use imaginary numbers then comment, and I'll give it a shot.

I honestly have no idea what you are supposed to do. What else did the problem say? Did the problem say distribute, did it say find a, or whatever?