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Stu

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Nombre de usuarioStu
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 #10
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Rom:

all I mean is to write sqrt(x) instead of sqrt x or sqrtx where x might be some complicated expression.

no fancy chars or images needed.



Still don't get it, is the Sqrt which encloses everything under it the same as a parenthesis in and of it's self.. and the std of working is to apply anything under the tick first. And when I wrote all my other parenthesis mean to work them first? And that in the question it was kind of on topic, whether it had a punctuation error or not? So I should have wrote -->[-b+-(Sqrt (b2(-4*a*c)))/(2*a)] as opposed to [-b+-(Sqrt b2(-4*a*c))/(2*a)] My questions are not Sqrt parenthesis, I am just putting them for purpose of seeing an order to solving only, relating to the question.


Melody:

Now Stu, is there any other specific problems that we can help with.
perhaps you should make sure you have digested the last 2 posts that Rom and I have made first...



Of course. I am just starting with quadratics and graphing for the week ahead and conic sections if able. So I will do for sure.

And yes, I just had this question regarding transposing a square root posted in this thread.
side question ot, when removing Sqrt in transposing given t= sqrt2mg, solve for g. it is easiest to remove the Sqrt first I get that, but answer given is g = t 2/2m. I was about to give this answer, but isnt everything under the Sqrt squared to remove it, so.. when transposing /2m shouldn't they be squared. I get that it isn't so I would just like to know why as I'm sure it is a simple answe.r. thanks. ie can't move the Sqrt with out moving the 2m to the left and squaring it also?
15 feb 2014
 #3
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bump
13 feb 2014