Stu

81 Questions
302 Answers

0

956

1

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Is this image conveying accurately?

is it accurate?
where did the 60 v come from?
do you have to draw on amp leaving battery to be correct? *fig 2.
why when take away the v source, do we leave 28 ohm when it it cannot carry current? is it just that when we cant lee mas ..

Stu 26 oct 2014

0

2033

7

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help with circuits

can anyone make then selc available to call or skype with to assist me with some cir uit fundementals tonight for an exam in the morning?

LancelotLink ●●●●●●●

Stu 26 oct 2014

0

1315

8

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Mesh/Kirchhoffs theorem.

can someone define the values in the equation one and two stated in the image please.

Alan ●●●●●●●●

Stu 7 oct 2014

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0

Stu23 feb 2014

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0

Stu23 feb 2014

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+3

What's harder to gain a thorough understanding of while under time constraints: Calculus or Vectors in Engineering?

Stu23 feb 2014

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so the 1/6 is the square of 86 by 36?
Also can't we surd the 86? If yes, how would that work exactly given the 1/6 in front of the 86?

Stu21 feb 2014

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Yeh, I knew it was simple. lol. I even went over this yesterday in a different example to flip the fraction which came to me after posting. Thanks for the reply. lol. Still have to absorb it, enough to remember all, apply as needed and enough to do method in reverse. It's a slow process when it's all new.

Nice wiki link.

Stu19 feb 2014

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solve log ₄(1/4).. What do I do with the fraction in a log situation. How in the instance described do I apply log _am ⁿ = n log _am. Oh It should be so easy. Got to work out some of the nuts and bolts I think with this one.

and working this to: 2 log _a5 + log _ap

Stu19 feb 2014

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That isn't that clear to me Rom. Also I'm unsure which part of the question you're answering specifically. Though I feel it's conversion process for any log function into a base 10 log. But it seems alien and a bit backwards, though I'm sure it's not.
Specifically, this does not expalin to me how it goes from a log 4 function to a log 10 function, or how to calculate a log 4 function manually, in steps (since I have the problems and the fomulae but not the method) and It does not really explain what is x b and c, where we have one equation, what's what.

logb(x) = logc(x) / logc(b)

so

log10(x) = logc(x) / logc(10)
If you could explain it a bit more thanks.

My interpretation would be logb is log input any base and it will be calculated by log original base by log new base. And what about powers? And how do we solve for powers? What's the step from log 2 or 4 or 7 etc.

Still would like to know the calculation method to manually calculate for example log ₄78. and maybe you can show a little bit of a more difficult log problem and solve to show me also. But I'd like to know the method of working through it specifically and where powers are involved. Ie. what's being Sqrt'ed, multiplied, divided etc to come up with an answer if any one would like to help.

Stu18 feb 2014

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I'd neglect to answer this question based on your user name. Please register a better name or take your energy elsewhere.

Stu17 feb 2014

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6 or 6 ones or six units.

Stu17 feb 2014

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Bump~ Title your posts well to find it again in search engine and to help others to do so as well.

Stu17 feb 2014