f(x)+2=ax^+bx^4+cx^3+2=(x^3+3x^2+3x+1)(dx^2+ex+f) (my head hurts)
If you multiply it out, you get these "variables"
a=d, b=e+3d, c=f+3e+3d, d+3e+3f=0, e+3f=0, f=2
Solve for abcdef
f(x)=ax^5+bx^4+cx^3
Yay!
desmos is a life saver, but I don't know how CPhill can make it bend to his will, how does he make it into a link?
I believe this question is one heureka already solved, the link is
https://web2.0calc.com/questions/find-a-polynomial-f-x-of-degree-5-such-that-both
That just means you're really good at math, CPhill...
forgot i could divide it.
RIP My mathematics career, Never-2021, Died by: EP.
From (-3, -5) to (6, 1), the line goes 9 right, and 6 up.
Then the the equation must be y=6/9x-3
9y=6x-27
9y-6x=-27
Yeah umm. It's not very possible with a GCD of 1.
9-6-27=-24
EDIT: RIP Varxaax, 2020-2021
Is that a test?
Late answer, bu hopefully still helpful.
If you take 90 and multiply it by 0.06, you get 5.4
You add 5.4 to 90 and get 95.4
That is 95 dollars and 40 cents.
Let's say each 2/3 cups is X
and X=6
4x=24
Now we need 1/6 of 2/3 which is 2/18
So you need 4 and 1/9
