vest4R

Thanks for your help pavlov. I've just found my error.

Upon calculating the term 132/dn * (dn-40). I used E as 200MPa for steel instead of 200GPa.

I appreiate your time.

unfortunately dn cannot exceed 460mm in this problem

ahhh yes. you're right

yeah I don't understand how it's 6.85 either. I was hoping someone could shed some light.

The third image shows how the 6.85dn was calculated

sorry, I wrote in the *10^-3 at the last second.

I've used 6852300 as Newtons

that's it!

Thank you, couldn't recall it at all!

Actually, I just realized how silly I've been for the past couple of hours trying to work this out.....

\(3Tcos\theta - 1.5Tsin\theta = 0 \\ 3Tcos\theta =1.5Tsin\theta \\ 3T = 1.5T tan\theta \\ \frac{3}{1.5} = tan\theta \)

I appreciate your help for waking me up!!

Thanks Melody,

Can I ask where: \(\frac{3cos\theta}{1.5cos\theta} = \frac{1.5sin\theta}{1.5cos\theta}\) came from?

is this just dividing the left hand side by only half of its self?

great! thank you. yes I got the same with: