After 1 minute the temperature will be 0.96*150
After 2 minutes the temperature will be 0.962*150
After 3 minutes the temperature will be 0.963*150
...
After t minutes the temperature will be 0.96t*150
What is t when the temperature is 100?
0.96t*150 = 100
Take logs of both sides
log(0.96t)+log(150) = log(100)
t*log(0.96) = log(100)-log(150) = log(100/150) = log(2/3)
t = log(2/3)/log(0.96)
t=log10(23)log10(0.96)⇒t=9.9325158624226383
t ≈ 9.93 minutes