Alan

7*10^-27*(3*10⁴)² = 7*10^-27*3²*10^4*2 = 63*10^-19 = 6.3*10^-18 

a² + b² = 256  

(a+b)² = 784  

Now (a+b)² = a² + b² +2ab  so 784 = 256 +2ab

2ab = 784 - 256 = 528

ab = 528/2 = 264

There are 9 possibilities for the person to the right of the host.  For each of those there are 8 possibilities for the person to their right.  For each of those ... etc.  This makes 9! arrangements in all.

$${\mathtt{9}}{!} = {\mathtt{362\,880}}$$ 

One thing you could try rosala, is going to the Customise and control icon (the three horizontal bars at the top right), click on that, select Tools from the pop-up menu, select Clear browsing data, and then choose to clear several weeks worth of browsing data.

I don't know if this will solve your problem, but it's worth a try.

There are an infinite number of such equations!  Do you have a list that you need to choose from?  If so, you need to say what ones are in the list.

The question is too vague.  Can you give a specific example of what you want to do?

Add the two angles together and divide by 2.

Multiply both sides by 7

x = 7*0.375

The following should help:

The rate of change of z with respect to x is just 2.73, which is positive, so the slope in the positive x-direction is up, and in the negative x-direction is down.

The rate of change of z with respect to y is -1.51 which is negative, so the slope in the positive y-direction is down and in the negative y-direction is up

Go with heureka's answer - I've changed my mind on this twice already!!