Alan

Assuming RS is a diagonal, then draw a line from the centre to T and you have an isosceles triangle.  The angle S (call it x) is the same as the angle between the line from the centre to T and that from T to S, so you have 2x + 48 = 180, from which you can find x.

What cone?!!!

Strangely, if you select the Answers tab and scroll down the page, you can see the image!  But if you go into the question and answer itself, the image is fuzzed out!!

Here's an alternative approach that doesn't require long division:

"...So it's not possible to put it in the same graph I was supposed to right?..."

Do you mean the graph background has to look just like in the image you uploaded?  You would need an electronic version that you can add information to (probably available on-line somewhere), or print off to add the data by hand (or get hold of an actual piece of real, old-fashioned graph paper, if such a thing is still manufactured!).

" I was wondering why you went for 1*10-3 and 1*108 instead of 1*10-4 and 1*107."

I decided to go with the powers of ten that I used simply because I figured it would be easier to type in the digits that way.  However, that's just personal preference; there's no great significance in it!   The graph was labelled automatically by the software I used.

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Like so:

You could use the online graphing facility Desmos if you don't have a piece of graphing software yourself.

There must be 2 non-athletes who are left-handed. Hence probability of randomly selecting student who is athlete or left-handed (or both)  is (35+2)/50 = 0.74

"Given that a and b are the roots of the equation 2x²+x+14=0 find the equation whose roots are a^4 and b^4."

(Note: I actually substituted in the order (x - b⁴)(x - a⁴))

Express this as \((a+b)^2 -ab=79\)

Rewrite as   \((a+b)^2 = 79 - ab\)

Look at all the perfect squares, say ps, less than 79.  Must have 79 - ab = ps  or  ab = 79 - ps

Look for two integers that satisfy ab = 79 - ps and (a + b)² < 79. 

I think there are only four pairs:

(-5, -3) 

(-3, -5)

(3, 5)

(5, 3)

One example:  n = -2 + (-6 + 3√10)i

|n| = √[(-2)² + (-6 + 3√10)²] = √[130 - 36√10] ≈ 4.02

Not sure I can prove this is a minimum though!