I guess 32) might be:
$$3\sqrt[3]{5y^3}\times 2\sqrt[3]{50y^4}$$
Multiply the terms outside the surds together, and multiply the terms inside the surds together:
$$6\times \sqrt[3]{250y^7}$$
Now you want to express the terms inside the surd as something-cubed multiplied by whatever is left over and can't be expressed as a nice cube!
$$250=2\times 5^3\\
y^7=y\times (y^2)^3$$
So:
$$6\sqrt[3]{250y^7}=6\sqrt[3]{2\times 5^3\times y\times (y^2)^3}=6\times5\times y^2\times \sqrt[3]{2y}$$
or just:
$$30y^2\sqrt[3]{2y}$$
But you must use brackets more to ensure your meaning is clear and unambiguous Nataszaa!