Hello BIGChungus! I like your name!
Plan:
For arithmetic problems, I like using variables.
First term = x
Common difference = y
We can define an arithmetic sequence this way:
x + (x + y) + (x + 2y) + (x + 3y)....
Set up and solve:
(1) a4a2=x+3yx+y=3
(2) a5a3=x+4yx+2y=?
Let us get rid of the fraction in (1) by multiplying both sides by (x+y)
x + 3y = 3x + 3y
-2x = 0
x = 0
Wow! The first term is 0.
Let us plug that into (2).
0+4y0+2y
Simplify
4y2y=2
Ta-da! Mathz! 