BuilderBoi

idk, probably some advanced method of coding 

There are 14 red marbles and 7 blue marbles in the bag. 

The probability of getting a red marble is \(2 \over 3\). The probability of getting a blue marble is \(7 \over 20\), because we already took 1 marble. 

Thus, the probability is \({2 \over 3} \times {7 \over 20} = \color{brown}\boxed{7 \over 30}\)

Sorry, this site is too addicting...

Also, it's not about getting here "first"... It's about helping people learn. 

grade 10? 

There can be: 

0 girls + 7 boys: \({4 \choose 0} \times {8 \choose 7} = 8\)

1 girl + 6 boys: \({4 \choose 1} \times {8 \choose 6} = 112\)

2 girls + 5 boys: \({4 \choose 2} \times {8 \choose 5} = 336\)

3 girls + 4 boys: \({4 \choose 3} \times {8 \choose 4} = 280\)

4 girls + 3 boys: \({4 \choose 4} \times {8 \choose 3} = 56\)

Adding everything up, there can be \(\color{brown}\boxed{792}\) committees.

\(x = 180 - 90 - 52 = \color{brown}\boxed{38}\)

Each picture has area \(9 \times 12\). There are 11 of these, so the total area is \(108 \times 11 = \color{brown}\boxed{1,188}\)

Where is C located among the 8 vertices?

The formula for diagonals is: \(s(s-3) \over2\)

We now have an equation to solve: \({s(s-3) \over 2} = 6s\)

Simplifying: \(s^2-3s=12s\)

Converting to a quadratic, we get: \(s^2 - 15s = 0\)

We know that \(15s = s^2\), so there are \(\color{brown}\boxed {15}\) sides. 

Write as a system of 3 equations: 

\(r = 8+i\)                       (1)

\(s = 4r\)                            (2)

\(i+r+s=96\)              (3)

Rearrange (1) so \(i\) is the independent variable: \(i = r - 8\)

Now, substitute i and s in terms of r: \(r + 4r + r-8 =96\)

Simplify: \(6r - 8 = 96\)

Add 8 to both sides: \(6r = 104\)

Divide by 6: \(r = 17 {1 \over 3}\)

Now substitute \(r\) into (1) and solve for \(i\): \(17 {1 \over3} = 8 + i\)

Subtract 8 from both sides: \(i = 9 {1 \over3}\)

Now substitute \(r\) into (2) and solve for \(s\): \(4 \times 17 {1 \over 3} = s\)

Simplify: \(s = 69 {1 \over 3}\)