ElectricPavlov

Slope = rise/run =   100/-50 = -2

Distance = sqrt (100^2 + 50^2) = 111.8 units

Yah....you are correct...that was a typo

uW = micro watt

I don't think you are interpreting the info correctly......        two points on a line  EACH would have TWO coordinates.     WIthout this info...or a picture of the line.....you cannot say anything about it.......It could have positive or negative slope of any magnitude.....  Sorry    .

If it is going DIAGONAL (i.e. it is sloped) from the top right to the left it has a POSITIVE slope.  

"The line is going diagonal from the top right down. 2 and -3 would be the order it hit the points."     if you are reading from RIGHT to LEFT....this line has a positive slope.......but you need more information to determine the MAGNITUDE of the slope......

there are INFINITE lines that go through    2   and -3    with positive slope,,,,,,,,

The REFLECTED wave decays by the 4th power....the transmitted wave at a distance only decays by the 2nd power....sooo

Power ~ k/x^2

4 uW/m^2 = k/175^2        4 (175^2) = k

?? = k/350^2

4(175^2) /(350^2)  = power at 350 = 1 uW/m^2

Fixed typos...Thanx Chris !    Answer not changed.....

That's just ONE point....or two lines....

1 Dunno....you're a 'Pooper-Pepper'   Haha

3 Man had just started crossing railroad trestle

2 CAR door !

It has a NEGATIVE slope if it is higher on the left and slopes down to the right.....

That is a solid dot at zero....so zero is included ....first Q should be answer  #4  or  D

Q 2  is the first choice    A>B in 1 hour

Sorry....this Q makes no sense..... what info did you omit?

If you meant    pi r^2 h    then just substitute in the values given and calculate....silly!

Are you studying Newton's Law of Cooling?    I THINK this is how to solve this Q:

T(t) = Ta + (Ti-Ta)e^-kt       Ti = initial temp    Ta = Temp ambient

T(t) = 126   =  70 + (180-70) e^-k5     results in k = .1350257

           120 = 70+ (180-70)e^-(.1350257t)         t = 5.84 minutes   =   5 minutes 50 seconds