ElectricPavlov

The square is 3 x 3 = 9 sq units

The line draws a triangle   height 2  base   3     area   = 1/2 bh = 1/2 (2)(3) = 3 sq units

9 - 3 = 6 sq units above line      or    6/9   or  2/3 above the line

Cosine of an angle in a RIGHT triangle = Adjacent leg / hypotenuse

soooo

Cos p = 10/15 = 2/3

This is also the cos of angle T

Cos T = 6/x = 2/3        so x = 9

Hint:   Angle z  + 108   add to 180 degrees (a straight line)

Once you find z    all of the interior angles add to 360 ... so you can find y

y= 1/2 x +14

2y-x = 44         Hint:   these are equations of lines that do not cross....so no solution set

                take it away !

Let x = Adult price

 Let y = student price

Then you have the following system of equations:

3x + 9y = $ 75     and

8x + 5y = 67        Now solve....

SInce 3x + 9y = 75      if we divide through by 3

            x+3y = 25        re-arrange

             x = 25 -3y       Sustitute THIS value of 'x' in to the second equation of the set

8 (25-3y) + 5y = 67     and solve for y

200 - 24 y + 5y = 67

-19y = -133

y = student price = $ 7     

      NOW, substitue THIS value of y into either one of the first two equations to calculate  x ...the adult price...

        ,,,,,,,,.you should be able to finish,,,

PEDMAS says parentheses first       then Mult or Division    then  add or subtract

7+(10-4)2  / 4

7 + (6)2 /4

7 + 12/4

7 + 3

10

Usin PEDMAS , you must do the MULTIPLICATION first ....then the SUBTRACTION

7 x 4 - 5 =

28 - 5=

23

I believe if I remember correctly, the sampling rate should be TWICE the highest frequency  ...    so    8 kHz sampling rate.

I'll have to review the second part of your question...

   but maybe each sample will need to be  2^x = 4096     where x is the numer of bits   = 12 bits long

      12 bits / sample   x   8 kHz  = 96000 bits/sec      9.6 x 10^4 bits/sec

The  -   1/2   means put everything in the denominator and take the square root....

1/(3xy^3)

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