geno3141

After simplifying all the multiplications and divisions, you get:

Numerator:  (20) * log(5) * log(e) * log(2) * log(100)

Denominator:  log(20) * log(25) * log (16)

The change of base formula says that ln(20) = log(20) / log(e)

         so log(e) / log(20)  =  1 / ln(20)

Now, the numerator that we have left is:  20 *  log(5) *  log(2) * log(100)

the denominator is:                                   ln(20) *  log(25) * log(16)

Now, log(100)  =  2   and    log(25)  =  log(5^2)  =  2log(5)    and    log(16)  =  log(2^4)  =  4log(2)

Making these substitutions, we have:

Numerator:    20 * log(5) * log(2) * 2

Denominator:  ln(20) * 2 * log(5) * 4 * log(2)

Cancelling, we end with:  5/ln(20)

(70x²)/(100x)  =  (70/100)(x²/x)  =  (7/10)(x)  =  (7x)/10

If this represents constant or smooth acceleration, then:

             acceleration = (final velocity - beginning velocity) / time

                               a  =  ( 15 m/sec - 24 m/sec ) / 12 sec

                              a  =   (-9 m/sec)/12 sec  =  -0.75 m/sec²

This is an indeterminate form; it flips back and forth from approaching +∞ to approaching -∞.

(9x + 6 - 4) / 2  =  8

First, multiply both sides by 2:

9x + 6 - 4  =  16

Simplify:

9x + 2  =  16

Subtract 2 from both sides:

9x  =  14

Divide by 9:

x  =  14/9

(1/4)(q - 12) + (1/3)(q + 9)

Use the distributive property:

(1/4)q - (1/4)(12) + (1/3)(q) + (1/3)(9)

(1/4)q - 3 + (1/3)q + 3

(1/4)q + (1/3)q 

Now, add 1/4 and 1/3:

    common denominator is 12:  1/4 = 3/12      and    1/3 = 4/12      so:       1/4 + 1/3  =  3/12 + 4/12  =  7/12

=  (7/12)q

440 ÷ 55  =  8 packs

According to the rules of operation, divide first, then subtract.

15.3 ÷ 3  =  5.1

5.1 - 0.5  =  4.6

Did you mean to type an equal sign in the problem; should the equal sign be a minus?

35^100

Because the answer is so large, very few calculators can give an answer to this.

If you need an approximation, you can get one using logs.

log(35^100) = 100log(35) ≈ 154.4; so an approximate answer is 10^154.4