(1/5)x + (2/3)y = -(3 1/5)
Problems are usually easier if there are no fractions:
(1/5)x + (2/3)y = -16/5
Multiplying both sides by 15:
---> 3x + 10y = -48
Substitution can occur when one of the equations is solved for one of the variables.
Since the other equation is 3x - y = 6
this equation can be solved for y: ---> -y = -3x + 6 ---> y = 3x - 6
Substitute this value for y into the other equation:
---> 3x + 10y = -48 ---> 3x + 10(3x - 6) = -48
---> 3x + 30x - 60 = -48
---> 33x - 60 = -48
---> 33x = 12
---> x = 12/33 ---> x = 4/11
If x = 4/11, then y = 3x - 6 ---> 3(4/11) - 6 = -54/11