geno3141

Try these one at a time:

The first formula:  m = h/55.

Replace h with 1, m = 1/55  --- this doesn't work.

The second formula:  m = 55/h

Replace h with 1, m = 55/1 = 55; replace h with 2, m = 55/2 =27.5 --- this doesn't work.

The third formula:  m = 55h

Replace h with 1:  m = 55(1) = 55. Replace h with 2:  m = 55(2) = 110. Replace h with 3:  m = 55(3) = 165. Replace h with 4:  m = 55(4) = 220. Replace h with 5:  m = 55(5) = 275. Replace h with 6:  m = 55(6) = 330.    --- these all work!

Let's try these, one at a time:

The first formula:  s = 22w  

Using this equation, replace w with 1, and s = 22. Replace w with 2, and s = 44. Replace w with 3, and s = 66. Replace w with 4, and x = 88. Replace w with 5, and s = 110.

This works! This must be the correct formula.

If it didn't work, then try the second formula, etc.

As a common fraction, 3 1/3  =  (3 x 3 + 1)/3  =  10/3

And, 1 5/12  =  (1 x 12 + 5)/12  =  17/12

To divide common fractions, multiply by the reciprocal:

(10/3) ÷ (17/12)  =  (10/3 x (12/17)  =  (10 x 12) / (3 x 17)  =  120/51  =  40/17

If she wants 25% Fruit Loops, she needs to find 25% of 6 cups.

--->   25% of 6 cups   --->  0.25 x 6 cups  =  1.5 cups.

This formula describes a parabola. The highest point will be at its vertex.

The x-value of the vertex of the parabola  y  =  ax² + bx + c   is:  x  = -b/(2a)

For the equation:  h  =  -16t² + 96 t + 4, the values of a, b, and c, are:  a = -16, b = 96, and c = 4.

t  =  -b/(2a)  =  -96/(2·-16)  =  -96/-32  =  3

--->  So, it takes 3 seconds to get to its highest point.

To find how high it goes, substitute 3 back into the original equation:  h  =  -16(3)² + 96 (3) + 4  =  148 feet.

4² = 16

√4 = 2

How many times bigger is 16 when compared to 2?

Same question:  what number times 2 will give you 16?

--->   8 times   --->  16 is 8 times bigger than 2.

(1/2)·√(2)/2  =  [1·√(2)] / [2·2]  =  √(2)/4

Distance Formula:     d  =  √[ (x2 - x1)² + (y2 - y1)² ]

(x1, y1)  =  (2, -1)  --->  x1 = 2, y1 = -1             (x2, y2)  =  (-4, 2)   --->   x2 = -4, y2 = 2

--->   d  =  √[ (-4 - 2)² + (2 - -1)² ]  

--->   d  =  √[ (-6)² + (3)² ] 

--->   d  =  √[ 36 + 9 ] 

--->   d  =  √[ 45 ]

--->   d =  √9·√5

--->   d  =  3√5

If the problem is  y  =  .5x - 2x - 16:

--->   .5x - 2x - 16  =  0

--->       -1.5x - 16  =  0                                 (simplify)

--->              -1.5x  =  16                                (add 16 to both sides)

--->                    x  =  -10 2/3                         (divide both sides by -1.5)

If the problem is  y  =  .5x² -2x - 16

--->   .5x² - 2x - 16  =  0

--->     x²  - 4x - 32  =  0                              (multiply both sides by 2)

--->   (x - 8)(x + 4)  =  0                              (factor)

--->  either  x = 8  or  x = -4  

Were you solving a quadratic equation?  Did you use the quadratic formula?

What was the original problem?

I believe that a mistake was made before you got the answer (-3 +√11)/2.