happy7

Not sure what the GED test is.....so I couldn't even begin to tell you if there was an error with the test

$${\mathtt{10}}{\mathtt{\,\times\,}}{{\mathtt{p}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{41}}{\mathtt{\,\times\,}}{\mathtt{p}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{p}} = {\frac{{\mathtt{41}}}{{\mathtt{10}}}}\\ {\mathtt{p}} = {\mathtt{0}}\\ \end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{p}} = {\mathtt{4.1}}\\ {\mathtt{p}} = {\mathtt{0}}\\ \end{array} \right\}$$

Stats don't lie

Ummm...I'll try my best

You indeed can!

Like negative 1 is -1

15+45=60

20 is a factor

Woah CPhill....where'd you get that?

Let's use order of operations with CPhill's x=5

5+2=7

10+3*7

3*7=21

10+21=31

So CPhill=correct

And x=5

And it is fifths