$${\mathtt{10}}{\mathtt{\,\times\,}}{{\mathtt{p}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{41}}{\mathtt{\,\times\,}}{\mathtt{p}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{p}} = {\frac{{\mathtt{41}}}{{\mathtt{10}}}}\\
{\mathtt{p}} = {\mathtt{0}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{p}} = {\mathtt{4.1}}\\
{\mathtt{p}} = {\mathtt{0}}\\
\end{array} \right\}$$
.
) 