You mean a2 ?
\(a^2 \mbox{ is equivalent to } a \times a\)
Oops sorry forget to choose LaTeX
\(-7-(-2)\\ = -7+2\\ = 2 -7 \\ = -5\\ \therefore\text{-7-(-2) is -5}\)
-7-(-2)\\
= -7+2\\
= 2 -7 \\
= -5\\
\therefore\text{-7-(-2) is -5}
No, I think he is a liar. He wrote that he have found the answer to his own problem but until now no mathematicians have found that answer........
Try typing ' 2^4 = ' on the calculator.
It will show \(\mathtt{2^4=16}\)
\(2\cos(90)-\sec(90)\\ =2(1)-\frac{1}{\cos(90)}\\ =2(1)-\frac{1}{1}\\ = 2- 1\\ =1\)
\(\text{My align looks bad. I am going to make it look better.}\\ \begin{align*}2x&-5y&=&\quad8\\3x&+9y&=&\;-12\end{align*}\)
Add up the 2 equations.....
10x = 24
x = 2.4
Substitute the value......
5(2.4)+4y = 2
4y = 2 - 12 = -10
y = -2.5
My mom is not on this forum though XD haven't even registered but she does have great maths skills.
Perimeter of triangle = 16 + 3x + 4x - 3 = 7x + 13
Perimeter of square = Perimeter of triangle = 7x + 13
Each side of square = 7/4 x + 13/4
