MaxWong

Thx Melody :D

\(P-PL\\ = P(1-L)\)

Can't be further factorized.

Solve for 'it' XD

1/2 (it) +13 =37

1/2 (it) =24

it = 48

When I halve 48 the result is 13 less than 37, this statement is true!! :D 

Therefore x+9/8 = something with remainder 3.

\(x\pmod 8 \equiv 2\\ x+8\pmod 8 \equiv 2\\ x+9\pmod 8 \equiv 3\)

Guest #2 is actually wrong. Note that x is an positive integer and 8 is also a positive integer. The remainder won't be a fraction.

This could be solved using modulus maths like Guest #1 and I did.

Wow oops I forgot XDDD

\(x^2+8x-48=0\\ (x+12)(x-4)=0\\ x=-12\\ OR\\ x=4\)

Same ans as Guest #1

Se divide el numerador entre el denominador.
2/5 = 0.4
6/13≈ 0.46

Thanks to Google translate.

Yes. And same as Guest #1's answer.

\(x \times x^2 \\ = x^1\times x^2\\ = x^{1+2}\\ = x^3\)

\(-7-(-2)\\ = -7+2\\ = 2 -7 \\ = -5\\ \therefore\text{-7-(-2) is -5}\)