1(a) $500 x (1+2%)25 x 12
= $500 x 1.0230
= $905.6807920516769
≈ $ 905.68
(b)(i)(1+0.03391)1−1=0.0339
APR = 3.39%
(b)(ii) (2+0.03292)2−1=0.033170602.....
APR = 3.32.....%
(b)(iii) (4+0.03354)4−1=0.033923......
APR = 3.392.....%
(b)(iv) (12+0.03412)12−1=0.0345348......
APR = 3.45......%
Which of these gives the cheapest option when taking out a loan for two years?
3.29% p.a. compounded semi-annually.
How much interest would it cost to borrow $1,000 for two years under the cheapest option?
1000 x 3.32% x 2
= $66.4
(c) 1000 x (1+2.5%)4 x 10
= 1000 x 2.685063838
= $2685.1 approx.
(d) f(x) = 2 - 3ln(x) + 3x
f′(x)=3x+3f′(1)=31+3=6
f(x) = 2x2ex
f′(x)=2xex(x+2)f′(1)=2(1)(e)(1+2)=6e
g(x) = 1 + x2
g′(x)=2xg′(1)=2(1)=2
(e) f(x)=x3−2x2−4xf′(x)=3x2−4x−4f″(x)=6x−4
I don't know what's critical point and local maximum.......