MaxWong

$(\sqrt[3]{2589})^{10}$

$\LaTeX$ code:(\sqrt[3]{2589})^{10}

PS: With both sides = $(scale\space factor)^6$

I guess you mean surface area.

Let V₁ and V₂ be the volumes of the similar figures respectively.

Let A₁ and A₂ be the surface areas of the similar figures respectively.

$\frac{V_1}{V_2}=(scale\space factor)^3=(\frac{length\space of\space a\space side\space of\space V_1}{length\space of\space a\space side\space of\space V_2})^3$

$\frac{A_1}{A_2}=(scale\space factor)^2=(\frac{length\space of\space a\space side\space of\space V_1}{length\space of\space a\space side\space of\space V_2})^2$

$\therefore (\frac{V_1}{V_2})^2 = (\frac{A_1}{A_2})^3$

$2GB=2\times10^6KB$

$\quad Maximum\space Number\space of\space Pages \\ =\frac{2\times10^6}{8}\\=\frac{10\times10^5}{4}\\=2.5\times10^5\\=0.25\times10^6$

Round the number by yourself. Trust me, it's easy. 

$We \space will \space let\space the\space cost\space of\space the\space orange\space be\space $x$

$6 \times 0.80 + 20x = 12x + 11\times 0.80\\ 4.80 + 20x=12x+8.80 \\ 4.80+8x=8.80\\ 8x=4$

Do the last bit yourself. Trust me, it's easy.

$x^3+bx^2+cx+d$

This cannot be further simplified. 

-12x-9+7x=26 Combine Like Terms.

-5x-9 = 26 Add 9 to both sides.

-5x = 35 

Do the last bit yourself. Trust me, it's easy. 

$C=\frac{\sqrt7}{LA}\\ CA=\frac{\sqrt7}{L}\\ \frac{1}{CA}= \frac{L}{\sqrt7}$

I will not give the last step to you. Think of it yourself. (Tips: How to make the right hand side remain only a 'L'?)

$\boxed{a^{\frac{m}{n}}=\sqrt[n]{a^m}}\\ \quad{\frac{2}{9}}^{\frac{1}{4}} \\ = \space \sqrt[4]{\frac{2}{9}}$

10 x 365 x 24 x 60 x 60 seconds.

Do the multiplication yourself. Trust me, it's easy with a good calculator like the one on this website.