\(\left(\sqrt{24}\right)^3\\ =\left ( 2\sqrt6 \right )^3\\ = 2^3\times (\sqrt6)^3\\ =8\sqrt{216}\\ =8\sqrt{6^2\times 6}\\ =48\sqrt6\)
\(\sin 2x = -\dfrac{\sqrt3}{2}\\ \sin 2x = - \sin 60^{\circ} \\ 2x = (180+60)^{\circ}\;or\;2x=-60 ^{\circ} \\ 2x = \dfrac{4\pi}{3}rad\;or\;2x= \dfrac{5\pi}{3}rad\\ x=\dfrac{2\pi}{3}rad\;or\;x = \dfrac{5\pi}{6}rad\)
\(3\tan 2x=\sqrt3\\ \tan 2x = \dfrac{1}{\sqrt3}\\ 2x = \dfrac{\pi}{6}rad\;or\;2x=\pi + \dfrac{\pi}{6}=\dfrac{7\pi}{6}rad \\ x=\dfrac{\pi}{12}rad\; or\; x= \dfrac{7\pi}{12}rad\)
You can imagine that 2 minus signs crossed together is the plus sign.
6- (-4)= 6 + 4 = 10
59 or 60. Depends on the date.
If you were born on 5 July 2002 and you will be 59 years old in 1 July 2062
If you were born on 5 July 2002 and you will be 60 years old in 1 August 2062
Understand?
The second hand will turn 60 rounds per hour.
Length of each round = 60.72/60 = 1.012m = 101.2cm
Circumference = 2(pi)(radius)
Let rcm be the length of second hand
101.2 = 2(pi)(r)
r = 101.2/(2pi)
Use the calculator for it ;D
\(\left(\dfrac{s^6d}{rt^7}\right)^{-8}\\ = \left(\dfrac{rt^7}{s^6d}\right)^8\\ = \left (\dfrac{r^8t^{56}}{s^{48}d^8} \right )\)
That could not be further simplified.
Guest #2's answer means
\(\begin{array}{rlll}&-&5&.9\\-&&8&.2\end{array}\)
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Yay time for the rescue!!
\((x-9)^2=49\\ \sqrt{(x-9)^2}=\pm \sqrt{49}\\ x-9 = \pm 7 \\x = 16 \;or\; x = 2\)
Check: (16-9)2 = 72 = 49
(2-9)2 = (-7)2 = 49
