Melody

do you mean

$$18-\sqrt[3]{27}^3 = 18-27 = -9$$

arc tan is the same as inverse tan so...

atan( )

inverse cos may display as acos

inverse cos and arc cos are the same thing :)

$${\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}} = {\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{6}} \Rightarrow {\mathtt{x}} = {\mathtt{2}}$$

$${\mathtt{2}}{v} = {\mathtt{5}}{v}{\mathtt{\,-\,}}{\mathtt{6}} \Rightarrow {\mathtt{v}} = {\mathtt{2}}$$

$${\mathtt{v}} = {\mathtt{6}}{v}$$

$${\mathtt{v}} = {\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{v}}{\mathtt{\,\times\,}}{\mathtt{3}} \Rightarrow {\mathtt{v}} = {\mathtt{2}}{\mathtt{\,\times\,}}\left(\underset{{\tiny{\text{Error: Unknown Identifier}}}}{{\mathtt{v}}}\right){\mathtt{\,\times\,}}{\mathtt{3}}$$

You are right, the calculator won't do that.    

Yes Mellie, you made a typo.

3^2=9

Yes it does have a lot of great features :)

Insert them where ?  

No rude comments thank you very much  

This is a serious response!

I just googled "Nike Stefan Janoski shoes greys ans crystal mint" I think

I went straight to pictures of course :)

That has no solutions   the number must be between   -1 and  1  

you probably mean

3x^2 – 4, for x = –3

3*(-3)^2-4 = 3*9-4=36-4=32