Melody

Good explanation there Brodude :)

Thanks Gibson and Brodude,

A little 'trick' here 

$$9^{5/2} = (9^{1/2})^5 =(\sqrt9)^5=3^5=243$$

If you are good with numbers you can do that in your head :)

Yes, our troll is never too far away.  LOL 

Thanks Brodude,

why didn't you just turn them both upside down in the first place?  That would have been a lot simpler.

Also usually log refers to log base 10 and

ln refers to log base e :)

Alan has used the formula

s=ut+(1/2)at^2

when you said NO initial velocity we both assumed you meant initial velocity =0

Mahum and BrittanyJ

You BOTH need to use brackets !!!!

Alan has continued it here

Perhaps Alan will know.

He seems to work out lots of great calc features.   

A log is a power (or an exponent)

$$\\4^2=16\\
so\\
log_416=2$$

Perhaps if I was a sports person I might understand what you are asking  :/