Melody

I had a quick look at Wolfram|Alpha  and  I cannot tell whether it agrees with mine or not since mine is not finished :)

ok then, what about 

$$\\(1+\sqrt3i)^3\\\\
=(\sqrt3i+1)^3\\\\
=[(\sqrt3i)^3]+[3*(\sqrt3i)^2]+[3*(\sqrt3i)]+1\\\\
=(3\sqrt3*-i)+(3*3*-1)+(3*\sqrt3i)+1\\\\
=(-3\sqrt3i)+(-9)+(3\sqrt3i)+1\\\\
=-8$$

SO

$$\\\sqrt[3]{ \frac{14*\sqrt[3]{(1+3i)^3} }{2}}\\\\
=\sqrt[3]{ \frac{14*\sqrt[3]{-8} }{2}}\\\\
=\sqrt[3]{ \frac{14*\sqrt[3]{8}*\sqrt[3]{-1} }{2}}\\\\
=\sqrt[3]{ \frac{14*2*\sqrt[3]{-1} }{2}}\\\\
=\sqrt[3]{ 14\sqrt[3]{-1} } \\\\$$

I have yet to consider   $$\sqrt[3]{-1}$$

Does that look right or wrong to you Badinage?

Sorry Badinage and fiora,  I think you are right - I was suffering from brain freeze

I have not looked from there on Badinage, is the rest of Fiora's work correct?

$$\\(-1+\sqrt3i)^3\\\\
=(\sqrt3i-1)^3\\\\
=[(\sqrt3i)^3]+[3(\sqrt3i)^2(-1)]+[3(\sqrt3i)(-1)^2]+[-1^3]\\\\
=[3\sqrt3*-i]+[-3(3*-1)]+[3(\sqrt3i)]+[-1]\\\\
=[-3\sqrt3i]+[9]+[3\sqrt3i]+[-1]\\\\
=+[9]+[-1]\\\\
=+8$$

Hello :)))

Hi Fiora,  welcome to the forum.  

Did I talk to you before and suggest that you join and that you take that icon?

It looks great :))

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   Edited: this was wrong 

Great pic anon,

If you joined up a square out of there would make a great icon for you :)

This is a line so you only need to know two points.

when x=0   y=40+40*0 = 40+0=40     so that is  (0,40)

when x=1   y= 40+40*1=40+40=80   so  (1,80)  is another point

NOW just plot these 2 pointsand rule a line between them :)

sin of any angle must be between -1 and +1` so this question has no answer. :)

I am sorry that you are feeling so down.  Perhaps our little community can help a little.

There are a lot of nice kids that populate this place.  :)

5.099  the next number is less than five so  this is the answer.