Thanks Guest.
What a silly mistake I made,
Well how many ways can it be done if you ignore the reflection bit ?
just fix one in place first and see how many permutations there are for the rest.
I am not so sure about the reflection bit BUT if the first one is fixed in place then how many axes of symmetry are there?
I am reasonably sure I answered this one recently so why not just google it ?
I'd give you some guidence if I had any but I really don't
I'd play around some more with when trippled can or cannot go together but I do not have any brainwaves.
Here is where it was asked last time.
Seems you will be accused of cheating....
https://web2.0calc.com/questions/help-quick_12
First I will state that i haven ot attempted to work this out.
Someone else answered last time.
So you have worked out that these cannot be together
1,2,3
2,3,4
3,4,5
4,5,6
5,6,7
6,7,8
7,8,9,
8,9,1
9,1,2
Mmm
There are lots of others too. like 3,6,9 etc
This is really tricky.
What have you done already towards solving this ?
Have you worked out which triples add to a multiple of 3?
This question was answered not that long ago.
I expect that you mean the numbers 1,2,3,4,5,6,7,8,and 9
Is this what you mean?
\(log_3 x=81\\ 3^{log_3 x}=3^{81}\\ x=3^{81}\)