I am considering this.
5*5=25
4*6=24
3*7=21
2*8=16
1*9=9
Each time the two numbers add to 10.
Their product seems to be at its biggest when the two numbers are the same.
The more different the two numbers are, the smaller the product appears to get.
So, I think you should be able to extend this observation in order to answer (or at least attmpt to answer) your question.
simplify n+1 divided by n squared - n - 2 divided by n squared-1
Is this what you want or do you need to put brackets somewhere?
\(\frac{n+1}{n^2}-n-\frac{2}{n^2}-1\)
Warum ist das Heureka? Ich verstehe nicht.
Ich spreche Deutsch nur einen bisschen.
Ich übe nur.
Antworten Sie daher bitte hauptsächlich auf Englisch.
Danke
+2,+3,+7, +1, and lastly -1.
-2,-3,+7, +1, and lastly -1.
-2,+3,-7, +1, and lastly -1
+2,-3,-7, +1, and lastly -1.
Looks like you could be right.
Hi Coolstuff,
As a teaching suggestion you could have just factorised the top and let the asker copy your method to factorise the bottom by themselves.
Yes, sounds good.
You found this 5 : 2,3,7,1, and lastly -1.
they could also have been
-2,-3,7,1, and lastly -1.
In fact I think there are many other groups of 5 roots that would work.
Can you work out how many groups of 5 exist?
At least you question is readable since you edited it.
It wasn't readable when it was answered LOL.
Do you ever do any questions for yourself?
Just factorize the top and the bottom then cancel.
maybe 13.
I äm going with 13, that is till I change my mind again.