Melody

please include the address of the first question.

The question asks only  for  angle BPC

ABE is an equilateral triangle so all the angles are 60 degrees.

so

angle PBC= 30 degrees

so

angle BPQ=60 degrees

Now,

Angle QPC = angle DAC = 45 degrees     Corresponding angles on parallel lines

So  

Here is my graphical solution.  (I know it is not what you want.)

Water is spraying from a nozzle in a fountain forming a parabolic as it travels. The nozzle is 10cm above the surface of the water. The water achieves maximum height of 100cm above the water surface and lands in the pool. The water spray is again 10cm above the surface of the water when it is 120cm horizontally from the nozzle. Origin is at the surface of water directly below the nozzle. I got -1/4(x-60)^2 + 100 but the answers say k supposed to be 90? Can someone explain how origin works

I decided to start with the origin (0,0) at the point that will become  (60,10) later on.

the height of the water jet is 90 units above the axis, and it crosses the x axis at =+/- 60

so

y=k(x-60)(x+60)

sub in (0,90) and I get 

90=k(-3600)

k=-1/40

so far the equation is    \(y=\frac{-1}{40}(x^2-3600)\)

Now I have to translate it into the correct position

\(y-10=\frac{-1}{40}((x-60)^2-3600)\\ \)

you can finish it.

Here is a link to the graph

Hint:

The little triangle is half of an equilateral triangle.

Use angle sum of a quadrilateral

then

trigonometry.

You are welcome Kes

I think you are making hard work of it

the inverse of   

\(y=5^{logx}\)

is simply

\(x=5^{logy}\)

You just have to switch the x and y over.

there would be restrictions on x and on y but the question isn't worrying about that.

Here is the graphs

It is a stupid question.     (I'd want to cry too)

The percentage is the rate.

I suppose they mean,     1) R,     2) B,    3) P

But it is still a badly worded question.