Melody

Why don't you become a member.

You seem like someone that answerers would like to know.

I am very aware that there have been a lot of registration problems lately but Admin hopes he has now fixed them.

If they are not fixed then the notigfications/complaints need to keep coming in. 

If you register then you could let us know if you had any problems ;)

Your right the first one is the best.

If you forget to do it then try the second one.  But you are right occasionally it refuses to cooperate.

If the second one fails then you can use the third one.

Alo:

Sometimes it is also impossible to get the Latex back up for editing which is the main reason why i usually add the Latex (not rendered) at the bottom of the post.  I figured someone would eventually ask me why I did this. But noone ever has :))

Mind you, I also leave the unrenedered LaTex there becasue someone might learn something from it. 

I actually used a different, although probably not easier method to Slimesewer

I said that if the ratio fo areas is 2 to 9 

then the ratio of the sides is   sqrt2  to  sqrt9

hence on my pic the first sides I could label were   sqrt(2) *x     and    3x

Then I took it from there.

I got the same as slimesewer, good work!

Sorry Chris, I believe you made a mistake somewhere.  

I draw the scale pic (just for fun)

I counted 

2(3+13+16+13+3) = 96

I will do the more difficult one and then you can almost copy and do the easier one.

'a' is a negative number so to stop my own confusion I let   a=-t    (so t is positive)

Now

cos(-t) = 0.8         (4th quad)

cos(t)=0.8

\(c=cos(-t+\frac{\pi}{6}) \\ c=cos(\frac{\pi}{6}-t )\\ c=cos(\frac{\pi}{6})cos(t)+sin(\frac{\pi}{6})sin(t)\\ c=\frac{\sqrt3}{2}*0.8+\frac{1}{2}*0.6\\ 10c=\frac{\sqrt3}{2}*8+\frac{1}{2}*6\\ 10c=4\sqrt3+3\)

If you do not understand then ask specific question, the mothod is almost identical.

LaTex:

c=cos(-t+\frac{\pi}{6}) \\
c=cos(\frac{\pi}{6}-t )\\
c=cos(\frac{\pi}{6})cos(t)+sin(\frac{\pi}{6})sin(t)\\
c=\frac{\sqrt3}{2}*0.8+\frac{1}{2}*0.6\\
10c=\frac{\sqrt3}{2}*8+\frac{1}{2}*6\\
10c=4\sqrt3+3

I communicated with Admin today.

He said he has spend a lot of time on the registration problem and hopes that it is fixed but he is not sure if 'the fix' may lead to other perhaps different problems. 

I am sure people will continue to use the flag button to report ongoing problems (which is the main way that it should be done)

Polite posts on the forum just informing people of their problems/experience, or private messages to me personally are also acceptable but please understand that i cannot personally fix your problems.  (It is just good that I am aware of general problems that people are having)

Thanks eveyone for your patience.

We are all aware that there are problems on this site but the owner has provided it, free of charge, for our use.

I and others have told the owner of the problems, I expect that now we have to be patient till he has time to fix them.

First you say admin is never here then you say the problems are his fault.

If he is not here then how do you expect your comment to help the situation?

I think you were just airing your frustration, I didn't think it was helpful so I blanked it out.

In a short time I will white out this thread as well, I just want you to read my comment first.

I answered thie question very recently.

Go find it.

If you new how to do it you would have already posted a pic.

Not just made slide, inane remarks to others.