Melody

WOW 

Thanks Alan,

That was a lot to display.  But I get it.  

Thanks!

Thanks but  please show some working Vinculum. 

I have no idea how you got this.

I'd like to see someone answer this too.  

Good work!! 

if f(x) is perpendicular to g(x) then  a= -1/3

what is g(-1) ?

What is f( of your answer) ?

half of 12 is 6 and so a part of this will be  (x+6)

The 'a' will just be 1 since 1 is the coefficient of x^2

So it is going to be   (x+6)^2 + v

I will leave you to work out what v is. 

Hint:  Do the expansion.

Thanks Ginger.

My problem is that I do not understand the question. 

(And at present I am too unenthused to try and work it out from what you have said.)

Maybe I will become more enthused later...

I answered a different question.  

I think it is just    

\(\displaystyle \frac{8!}{64C8} \)

It is a power of 4 so there are 4 solutions

this is one way to tackle it
\(x^4=-64\\ x^2=8i\qquad or \qquad x^2=-8i\\ x=\pm\sqrt 8 [\sqrt i] \qquad or \qquad x \pm\sqrt 8\sqrt{-1} [\sqrt i] \\ x=\pm\sqrt 8 [\sqrt i] \qquad or \qquad x \pm i\sqrt 8 [\sqrt i] \\ x=\pm2\sqrt 2 [\sqrt i] \qquad or \qquad x \pm2 i\sqrt 2 [\sqrt i] \\ \)

Now you need to check what I have done and work out what the square root of  i  is.

there is lots of places on the internet help you to learn how to work this out.

Here is one:

A and B working together can finish a job in 40 days. They worked together for a number days and A left the work. B alone finished the remaining work in 24 days. For how many days did they work together? 

there will be no exact number answer if they work at different rates so I am going to assume that they both work at the same pace.

So it it takes the two 40 days to do the jobs, I will assume that it will take one 80 days.

So in 24 days one will be able to do    24/80   of the job

So that means that 56/80 was already done.

\(\frac{56}{80}*40 = 28days\)

They worked together for 28 days.