Melody

@@ End of Day Wrap - Fri 13/6/14   Sydney, Australia   Time 10:10pm  

Hi Everyone,

Great answers today from CPhill, reinout-g, Rosala, zegroes, Alan, Will85237, and Bertie.

Will85237 joined a couple of days ago. Welcome to Web2.0calc forum. We hope that you enjoy yourself here.

NinjaDevo made his way onto the "Top Answerers" board today.  CONGRATULATION NINJADEVO.  I had not realised that you had answered so many questions,  (Ninja's are supposed to be stealthy) But, I have been very impressed with the quality of your answers Ninja. Thank you.

There have been a  number of questions lately which are ambiguous or simply do not make sense.  At Alan's suggestion I have posted a note question askers, requesting them to be careful about this and also giving hints to appropriate forum conduct.  This is it.

Actually we are all equally correct I think.  The question does say when the first deposit is made!

If it is made at the begining of the first month then CPhill is correct (Present value of an annuity due question)

If it is made at the end of the month then I am correct. (present value of an ordinary annuity problem)

CPhill answer is probably preferable.

Thanks Chris and Alan for making me think about it.

13/6/14

Note for question askers

deleted deleted

It is already an algebraic expression

$$\sqrt5*x^3$$

Can you give us and example please and we will show you.

say 

$$y=3x+2$$

when x=0

y=3*0+2=2

so (0,2) is one point

When x=1

y=3*1+2=3+2=5

so (1,5) is another point.

Is this what you mean?

No it is not.  I usually just stick these things up on the forum every now and again.

I am  assuming that each colour is equally represented so each spin there is 1/3 chance of getting a yellow.

$$\mbox{P(7out of 10 yellow) =}10C7 * (1/3)^7 * (2/3)^3$$

$${\left({\frac{{\mathtt{10}}{!}}{{\mathtt{7}}{!}{\mathtt{\,\times\,}}({\mathtt{10}}{\mathtt{\,-\,}}{\mathtt{7}}){!}}}\right)}{\mathtt{\,\times\,}}{\left({\frac{{\mathtt{1}}}{{\mathtt{3}}}}\right)}^{{\mathtt{7}}}{\mathtt{\,\times\,}}{\left({\frac{{\mathtt{2}}}{{\mathtt{3}}}}\right)}^{{\mathtt{3}}} = {\mathtt{0.016\: \!257\: \!684\: \!296\: \!093\: \!1}}$$

there is no times in there

It is just 

sin^-10.8=Inverse sin 0.8 = arc sin 0.8 = asin0.8

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}^{\!\!\mathtt{-1}}{\left({\mathtt{0.8}}\right)} = {\mathtt{53.130\: \!102\: \!354\: \!156^{\circ}}}$$

ok so I had to put the brackets in to make it work.