Melody

30) √8x^5*√3x

$$\sqrt8x^5\sqrt3x = \sqrt{24}x^6 \\\\$$

There is no cubed root in this question. 

$$\sqrt{54}$$

You need to find a squared number that goes into 54.  If there is not one then you cannot simplfy!

Square numbers are 4,9,16,25,36,49, etc (1 is not helpful)

9 goes into 54.

$$\sqrt{54}\\
=\sqrt{9*6}\\
=\sqrt9*\sqrt6\\
=3\sqrt6$$

I am sorry but this question does not make sense.   

I am not sure what you are actually asking.  

It would be better if you helped this person learn how to do the question Zegroes.  

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there  are 2 ways

15% of 32.50 = 15/100*32.50 = $4.875  

$32.50 - $4.875 = $27.625

So either $27.62 or $27.63

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OR

100% - 15% = 85%

85% of $32.50 = 85/100*32.50 = $27.625

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There is not enough information here to give any answer.  Many functions and relations would meet these criteria. 

Do you mean an yearly income of $70,000 for ever?  (A perpetuity?)

Is  this your question?

How much will I need to save every year in order to retire with a perpetuity of $70000 paid at the end of each year into perpetuity?  Assume the money earns 5% per annum .

If this is your question then I will answer it.  Let me know.  

It depends on what other information that you have.

If you have another angle then you can use the angle sum of a triangle (180degrees)

If you have 2 sides then you use inverse trigonometry.

$$\frac{4}{(2-3x)}-\frac{1}{(1+x)}+\frac{3}{(1+x^2)}\\\\
=\frac{4(1+x)(1+x^2)}{(2-3x)(1+x)(1+x^2)}-\frac{1(2-3x)(1+x^2)}{(1+x)(2-3x)(1+x^2)}+\frac{3(1+x)(2-3x)}{(1+x^2)(1+x)(2-3x)}\\\\
=\frac{4(x^3+x^2+x+1)}{(2-3x)(1+x)(1+x^2)}-\frac{1(-3x^3+2x^2-3x+2)}{(1+x)(2-3x)(1+x^2)}+\frac{3(-3x^2-x+2)}{(1+x^2)(1+x)(2-3x)}\\\\
=\frac{(4x^3+4x^2+4x+4)}{(2-3x)(1+x)(1+x^2)}+\frac{(3x^3-2x^2+3x-2)}{(1+x)(2-3x)(1+x^2)}+\frac{(-9x^2-3x+6)}{(1+x^2)(1+x)(2-3x)}\\\\
=\frac{(4x^3+4x^2+4x+4)+(3x^3-2x^2+3x-2)+(-9x^2-3x+6)}{(2-3x)(1+x)(1+x^2)}\\\\
=\frac{7x^3-7x^2+4x+8}{(x^2+1)(-3x+2)(x+1)}\\\\$$

I think that is ok.  It hasn't simplified very nicely - maybe I made an error somewhere 

More info needed.  How many people?  How many are coupled?