Melody

Hlow many significant figures?  - Are you supposed to be estimating it or doing it on a calculator?

$$\left({\frac{\left({\mathtt{2.99}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{6}}}\right)}{{\mathtt{44.892}}}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{146.04}} = {\mathtt{66\,750.334\: \!751\: \!848\: \!881\: \!760\: \!7}}$$

You are welcome. If you need more help post again but study what I have given you first. 

Why don't you join up.  It is very easy and we get to know you that way.  

Quadratic equation links:

What do you mean "you try to solve them"?

I didn't know that they needed solving. 

arcsin is the same thing. Use asin

Thanks Rosala and anonymous,   

You should edit your answer to make it correct.  BUT make sure write "edited" in there too.:) 

$$\\3(h^3+h^2)=108\\\\
h^3+h^2=36\\\\
\mbox{I don't know how to do this without 'guessing'.}\\
\mbox{So I am going to present if easier for guessing}\\\\
h^2(h+1)=36\\\\
That\; is\;\; 9*4=36\\\\
h=3 \\\\
\mbox{So that is one solution - it is a cubic so there are 2 more but they might be imaginary numbers}\\\\
\\$$

Here are the answers.  There is only one real one.  

Thanks Alan

Your idea of simplfying the numbers as you go will probably be much better for Rosala.

Maybe i should go back an incorporate it into my answer.  Normally I would but the numbers cancelled out so nicely that I didn't force myself to do it that way.  :)

I think i will wait till she comments more.      

Mon 8/9/14

1) This one provided some humour and it is very comforting for a queen to know that her kingdom is so fiercely defended.   

@@ End of Day Wrap:      Sun 7/9/14        Sydney, Australia      Time 6:15pm     ♬

Hi all,

I powered through the questions last night and today (along with Aziz) and at a glance they all seem to have a reasonable answer.  Right back to the last proper wrap which was last Thursday.  I am very pleased about that.     (With the exception of a couple of high end commercial questions)   

Now for the credits.  Our great answerers over these few days have been HaleyWoodall17, Alan, AzizHusain, CPhill, Rosala, NinjaDevo, Honga, Kitty<3, Blazinkurama, DragonSlayer554, DevSeth, Heureka, Helen1709 and LLABlackJack.  A big thank you to each of you.  

Blazinkurama and DevSeth are both new.  I like to take this opportunity to welcome you to web2.0calc forum.  We all hope  that you enjoy yourselves here.   

Now for a few interest threads:

1) is it divisable by 3 - I handy trick to know (Thanks Alan)