It is actually 101/2 = 50.5

Or the average of 50 and 51 which is still 50.5

But yes google would have been much quicker for you.

Yes I like CPhill's answer too.   

I'll look at the annuity first.  It is just the future value of an ordinary annuity.

$$\boxed{FV=R\times \right[\frac{(1+i)^n-1}{i}}\\\\
i=0.05/4=0.0125\\
i+1=1.0125\\
R=$556.19\\\\
FV=556.19\times \right[\frac{(1.0125)^n-1}{0.0125}$$

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Now I will look at the simple interest scenario.

interest = 1% per quarter

$$\\\boxed{FV=P(1+rt)} \qquad \mbox{In this interest t is number of quarters=n}\\\\
FV=7400(1+0.01n)\\$$

So we need to find the smallest n where

$$\\556.19\times \right[\frac{(1.0125)^n-1}{0.0125}\;>\; 7400(1+0.01n)\\\\
(1.0125)^n-1\;>\; \frac{0.0125\times 7400(1+0.01n)}{556.19}\\\\
(1.0125)^n-1\;>\; 0.16633998(1+0.01n)\\\\
(1.0125)^n-1\;>\; 0.16633998+ 0.0016633998\;n\\\\
(1.0125)^n-0.0016633998\;n\;>\; 1.16633998 \\\\$$

Now this looks pretty horrible so I just solved it by trial and error.

When n=10  LHS=1.11     So n is bigger than 10

When n=20  LHS=1.248    So n can be smaller than 20

When n=15 LHS=1.179     n can be smaller but its getting close

When n=13 LHS=1.154    So n must be bigger than 13

When n=14  LHS = 1.1666   this satisfies the condition.

So the smallest value of n that satisfies this condition is n=14

14/4=3.5years

the annuity will be bigger than the simple interest scenario in 3.5 years time.     

y^16

that is the answer

There are 12 different cards in the bag.  You could choose any of them.

Is your question complete?

Try hitting 'enter'on your keyboard instead.

It should work either way.

Maybe this will help.

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Debería funcionar de cualquier manera.

Tal vez esto ayudará.

http://web2.0calc.com/questions/how-do-i-type-in-fractions

Yes!

It is also rational and real

Why don't you do it here with the calculation button and show me that you can?  

I'd like you to do that.  

5:x+2=4:x

I think that the question is supposed to be

5:(x+2)=4:x

$$\\\frac{5}{x+2}=\frac{4}{x} \\\\
\frac{x+2}{5}=\frac{x}{4}\qquad \mbox{I turned both sides upside down}\\\\
\frac{20(x+2)}{5}=\frac{20x}{4}\qquad \mbox{I multiplied both sides by 20}\\\\
4(x+2)=5x\qquad \mbox{}\\\\$$

You should be able to do it from here.

I don't know, use the 'calculation' button and she me what you entered please.