Melody

I guess not

6*1000=6000

Have a look at this.     

you could multiply or divide it by negative 1

$$\\\frac{80.6}{4.096\times10^{-12}}\\\\
=\frac{80.6\times 10^{12}}{4.096}\\\\
=19.678\times 10^{12}\\\\
=1.9678\times 10^{13}\\\\$$

Correct to 5 significant figures.

You should 'study' this post.     

1)

$$\\F(x)=x^2+2\\\\
F(x^2)=(x^2)^2+2=x^4+2\\\\$$

3)

$$G(x)=3x^2-2x-1

G(a+b)=3(a+b)^2-2(a+b)-1\\\\
G(a+b)=3(a+b)^2-2(a+b)-1\\\\$$

You can expand and simplify this one.   

$$\\50+218x^3-28+12x^6\\
=50-28+218x^3+12x^6\\
=22+218x^3+12x^6$$

Look here for a general all inclusive answer.

Thanks you anonymous.  The answerers here all try their hardest to help.  

It is always so nice when people voice their appreciation.

Why don't you join up.  We love having such polite and grateful members and it would be nice to get to know you.      

Alan, I am a little confused.

The way I have drawn my v-t graph from the origin to  point P  is concave up.

If this is correct shouldn't the acceleration (between the origin and P) always be positive and decreasing.  

Thanks very much Alan,  

*** points P and R in the first picture ( x - t ) is a turning point but how did you know that p is the maimum velocity and R is minimum ? ***

I have assumed that P and R are points of inflection.

If this is the case then at P on the x-t graph has the steepest positive gradient hence it will have maximum velocity.

And

R on the x-t graph has the steepest negative gradient hence it will have the greatest negative velocity.

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Remember 3*15,

The gradient on the x-t curve IS dy/dx  which IS the velocity.

and

The gradient on the v-t curve is  dv/dx which IS the acceleration.

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