NinjaDevo

150/350           ---Divide numerator & demoinator by 5

30/70                 Divide numerator & demoinator by 10

3/7

or you could have divided them both by 50 right off the bat...

Well, to figure out the volume of a cylinder, we can use 

V = (pi)*(r²)*(h)          ---Pi times radius squared times height 

Let's fill in what we know, and it should give us what the height is.

V = (pi)*(r²)*(h)

478.85 = (3.14)*(5²)*(h)         ---Radius is half of the diameter

478.85 = (3.14)*(5²)*(h) 

478.85 = (3.14)*(25)*(h) 

478.85 = (78.5)*(h) 

478.85 = 78.5h

÷78.5      ÷78.5           ---Divide both sides by 78.5

6.1 = h

h = 6.1

So the height of the cylinder is 6.1 cm.

Let's check it:

V = (pi)*(r²)*(h)

478.85 = 3.14*5²*6.1

478.85 = 3.14*25*6.1

478.85 = 3.14*15.25

478.85 = 478.85

It works!

I'm not sure on what you want us to do here...

Perhaps you want us to simplify this equation?

In that case...there's not much to simplify. But, u = (a + b)/2  is the same thing as

u= a/2 + b/2

Is this what you're looking for?

I'm the procrastinating the fact that I have to mow the lawn today.

I didn't have anything better to do so I answered this question. 

Mathematically, this is how I would find the square root of a given pencil:

We first need to find the volume of the pencil, then find the square root of the volume. This is technically the square root of the volume of the pencil, but bear with me.

We could break the pencil down into two basic parts, a cone, and a cylinder:

Now, this would depend on how much your eraser is worn down. Also, the body of a pencil isn't a complete cylinder. This is only an aproximate value, then.

To find the volume of the cylinder, use this equation

V = (pi)(r²)(h)

To find the volume of the cone, use this equation:

V = (pi)(r²)(h/3)

Add these two values together, then find the square root of the sum.

This is the square root of your pencil!

Wow...I must be really bored today to give a detailed answer to a question like this.

36 ÷ 6 = 6!

How I've seen some forums do it is when you go to the forum, the first "question" that appears is the sticky topic, and then all other questions that people post go below that.

That way, if people are just posting a question without looking around on the site too much, they will see that sticky before they post something.

I'm not sure if you have this capability on this site, but I think this would work well for our current predicament.

mínimo común múltiplo es 144

8 multiplos: 8, 16, 24, 32, 40, 48, 56, 64. 71, 80, 88 , 96, 104, 112, 120, 128, 136, 144

36 multiplos: 36, 72, 108, 144

48 multiplos: 48, 96, 144

Oh yeah, that would make sence.

Is this meaning you would need to know the angle of line A-C for example?

Or just what a strait line measurement from A-C would be?