NinjaDevo

We just need to "translate" this to algebraic language and solve! (just need to set it up as an algebra problem)

Let's bold the key words here:

"the difference between twice a number and 8 is twenty more than nine times the number"

"difference" means subtract

"twice a number" can be written as 2N

"is" means equals or =

"more" means to add

"nine times the number" can be written as 9N

Let's write it out and solve for N:

2N-8=20+9N          ---Subtract 2N from both sides

-8=20+7N             ---Subtract 20 from both sides

-28=7N                ---Divide both sides by 7

-4 = N

so

N = -4

Let's have N represent the first mystery number.

Since we need to find the next consecutive odd number, it will be two more than that number.

Here's a list of coonsecutive odd numbers starting from one: 1, 3, 5, 7, 9, 11, 13...etc.

Here you can see that the next consecutive odd number is two more than the last. This means the second mystery number can be written as N+2

They add up to 124, so now we can write this as an algebra problem.

N + N+2 = 124           ---Combine the N's to get 2N

2N + 2 = 124              ---Subtract 2 from both sides

2N = 122                     ---Divide both sides by 2 so we get N alone

N = 61

This tells us the first mystery number...but the second one was 2 more than that. Now we add two to 61 to find the second number

61+2= 63

Now we have the two numbers. 61 and 63.

I'm doing well, how about you?

I believe the correct assignment of players for a 27 player bracket would be player 1 gets a bye, then 2 & 27 play, 3 & 26, 4 & 25...etc.

I'm not sure what you mean for "How about tournaments that eliminate on power 3?" Could you explain that better?

Thanks everyone for the positive feedback. :)

Also, thanks Alan for making sure the physics posts were correctly placed.

Finally, I did add those links to the original post here Melody. They seemed like some nice additions.

Yeah it was a quiet day!

To my count, there was only 17 posts between your last "end of the day wrap!"

$${\mathtt{100\,000}}{\mathtt{\,\times\,}}{\mathtt{100\,000}} = {\mathtt{10\,000\,000\,000}}$$

To solve this, we first need to turn the percent into a decimal, otherwise we would get a weird answer.

62.5% written as a decimal would be 0.625. You basically just move the decimal over two places to the left and take away the percent sign.

Now we have:

$${\mathtt{800\,000}}{\mathtt{\,\times\,}}{\mathtt{0.625}}$$

Multiply it out

$${\mathtt{800\,000}}{\mathtt{\,\times\,}}{\mathtt{0.625}} = {\mathtt{500\,000}}$$

So our answer is 500,000.