SpawnofAngel

We can write this as the power/power root

so in a sense it is

\(\sqrt[4]{10000^1}\)
sot he anwser is 10

I don't know the equation

I will just solve several of them

\((9*9*9)/9/(9*6)\)

729/(9/54)

729/(1/6)

729*6 = 4374

or

(729/9)/54

(81/1)/54

81/54

9/6

3/2

\(9*(9*9)9/(9*6)\)

9*(81/9)/54

9*(9/1)/54

9*1/6

9/6

3/2

or

9*81/(9/54)

9*81/(1/6)

9*(81*6)

9*81*6 = 4374

There are other possibilities as well

3*9+5*54/6

27+5*54/6

27+5*9

27+45

72

\(x/24 = 3/4\)

Multiply each side by 24 to cancel the 24 on the left and add it to the right

We multiply both sides because we ewould be changing the equation if we didn't

(3/4)*24 = 18

X=18

Sorry, misread it

Sorry for these sporadic posts, I just keep remebering things at times

8=(2log(E/10^11.8))/3

I'm going to assume that exponet is on 10

24=2log(E/10^11.8)

3 moved over

12=log(E/10^11.8)

Lets that the inverse of log which is B^E=L where B is the base, E is what is equal to the log, and L is the log

10^12=e/10^11.8

10^12*10^11.8 = 630957344480194300000000

e=6.3095*10^23 joules of energy

You do not need to solve for the variables to the equation to solve it

Since it is something being subtracted from itself, the anwser is 0

It is simply 3 and 5/6

But you can trun the 3 into 18/6 and combine like terms 

23/6

Actually it is undefined because of the division by 0