+0  
 
0
851
1
avatar

|x+1|^2 +2|x+1|-3<0

 14 oct 2014
 #1
avatar+1254 
0

|x+1|2+2|x+1|-3<0
x2+2x+1+2x+2-3<0
x2+4x+0<0

x1,2<(-b±√(b2-4ac))/2a
x1,2<(-4±√(42-4(1)(0)))/2(1)
x1,2<(-4±√(16-0))/2
x1,2<-4±4/2
x1<0
x2<-4

 16 oct 2014

2 Usuarios en línea

avatar
avatar